Knowee
Questions
Features
Study Tools

Prove by mathematical induction that11×2×3+12×3×4+ ⋯ +1n(n+1)(n+2)=14−12(n+1)(n+2).

Question

Prove by mathematical induction that

11×2×3+12×3×4++1n(n+1)(n+2)=1412(n+1)(n+2). 11 \times 2 \times 3 + 12 \times 3 \times 4 + \cdots + 1n(n+1)(n+2) = 14 - 12(n+1)(n+2).

🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, let's prove the given statement using the principle of mathematical induction.

Mathematical induction has two steps: the base case and the inductive step.

Step 1: Base Case Let's start with n=1. The left side of the equation becomes 11×2×3 = 6, and the right side becomes 1/4 - 1/2(1+1)(1+2) = 1/4 - 1/2(2)(3) = 1/4 - 1/3 = 1/12. So, the base case does not hold for n=1.

Step 2: Inductive Step Assume the statement is true for n=k, i.e., 11×2×3 + 12×3×4 + ... + 1k(k+1)(k+2) = 1/4 - 1/2(k+1)(k+2).

We need to prove the statement is true for n=k+1, i.e., 11×2×3 + 12×3×4 + ... + 1k(k+1)(k+2) + 1(k+1)(k+2)(k+3) = 1/4 - 1/2(k+2)(k+3).

Starting with the left side of the equation for n=k+1, we can substitute the inductive hypothesis:

11×2×3 + 12×3×4 + ... + 1k(k+1)(k+2) + 1(k+1

This problem has been solved

Similar Questions

Prove by mathematical induction that11×2×3+12×3×4+ ⋯ +1n(n+1)(n+2)=14−12(n+1)(n+2).

Using mathematical induction, prove that the sum of the first 𝒏 odd positive integersis equal to 𝒏𝟐

Using mathematical induction, prove that the sum of the first 𝒏 positive integers isequal to 𝒏(𝒏+𝟏)𝟐 .

rove by induction that for all n ∈ N,5 + 7 + . . . + (2n + 3)= ∑i=ni=1 (2i + 3) = n(n + 4)

The solution of the recursion relation an=8a(n-1)-16a(n-2), with a0=1 and a1=6 is an=_________.Question 6Answera.(1+n)4nb.(1+  n) 4nc.(1+2n)4nd.4(n+1)

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.