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Select the correct answer.Which expression is equivalent to 5⁢log𝑥⁡2−log𝑥⁡4? A. log𝑥⁡6 B. log𝑥⁡(52) C. log𝑥⁡28 D. log𝑥⁡8

Question

Select the correct answer.

Which expression is equivalent to 5logx2logx4?5\log_{x} 2 - \log_{x} 4?

A. logx6\log_{x} 6
B. logx(52)\log_{x} (5^{2})
C. logx28\log_{x} 28
D. logx8\log_{x} 8

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Solution

Sure, let's solve the expression step by step.

We need to simplify the expression 5logx2logx4 5 \log_x 2 - \log_x 4 .

Step 1: Use the power rule of logarithms. The power rule states that alogbc=logb(ca) a \log_b c = \log_b (c^a) . Applying this rule to the first term:

5logx2=logx(25)=logx32 5 \log_x 2 = \log_x (2^5) = \log_x 32

So the expression now is:

logx32logx4 \log_x 32 - \log_x 4

Step 2: Use the quotient rule of logarithms. The quotient rule states that logbalogbc=logb(ac) \log_b a - \log_b c = \log_b \left( \frac{a}{c} \right) . Applying this rule to the expression:

logx32logx4=logx(324) \log_x 32 - \log_x 4 = \log_x \left( \frac{32}{4} \right)

Step 3: Simplify the fraction inside the logarithm.

324=8 \frac{32}{4} = 8

So the expression simplifies to:

logx8 \log_x 8

Therefore, the correct answer is:

D. logx8 \log_x 8

This problem has been solved

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