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Use the calculation below to write out the original quadratic equation.x=−5±52−4(−3)(1)−−−−−−−−−−−√2(−3)

Question

Use the calculation below to write out the original quadratic equation.

x=5±524(3)(1)2(3) x = -5 \pm \frac{\sqrt{52 - 4(-3)(1)}}{2(-3)}

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Solution

The given expression is a solution for a quadratic equation using the quadratic formula, which is x = [-b ± sqrt(b² - 4ac)] / 2a.

Given x = -5 ± sqrt(5² - 4(-3)(1)) / 2(-3), we can identify the values of a, b, and c from the quadratic formula:

a = -3 b = -5 c = 1

The original quadratic equation is given by ax² + bx + c = 0. Substituting the values of a, b, and c, we get:

-3x² - 5x + 1 = 0

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