A line has a slope of 6 and passes through the point (–3,–18). Write its equation in slope-intercept form.

The slope-intercept form of a line is given by the equation y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Identify the slope (m) and the point (x, y). In this case, m = 6 and the point is (-3, -18).

Step 2: Substitute the slope (m) and the point (x, y) into the equation. This gives us -18 = 6*(-3) + b.

Step 3: Simplify the equation to solve for b. This gives us -18 = -18 + b.

Step 4: Add 18 to both sides of the equation to isolate b. This gives us b = 0.

Therefore, the equation of the line in slope-intercept form is y = 6x + 0, or simply y = 6x.