In binary search, average number of comparison required for searching an element in a list if nnumbers is# (A) n log2 .(B) 2/n .(C) n.(D) n – 1.(E)n/2
Question
Solution 1
The correct answer is (A) n log2.
Binary search is an efficient algorithm for finding an item from a sorted list of items. It works by repeatedly dividing in half the portion of the list that could contain the item, until you've narrowed down the possible locations to just one.
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