Find f.f '''(x) = cos(x), f(0) = 2, f '(0) = 6, f ''(0) = 5f(x) = 6x+1+cos(x)
Question
Solution 1
The problem seems to be a bit mixed up. Let's break it down:
- You're given that the third derivative of a function, f'''(x), is equal to cos(x).
- You're also given initial conditions: f(0) = 2, f'(0) = 6, and f''(0) = 5.
- You're asked to find the function f(x).
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