Given that f(1) = 2, f'(1) = -1, g(1) = 0, and g'(1) = 1. If F(x) = f(x) cos cos (g (x)), then the value of F'(1) is?"

Question

Given that f(1) = 2, f'(1) = -1, g(1) = 0, and g'(1) = 1. If F(x) = f(x) cos cos (g (x)), then the value of F'(1) is?"
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Solution 1

Para encontrar el valor de ( F'(1) ), primero necesitamos aplicar la regla del producto y la regla de la cadena a la función ( F(x) = f(x) \cos(\cos(g(x))) ).

Primero, recordemos que la derivada de un producto de dos funciones ( u(x) ) y ( v(x) ) es: [ (uv)' = u'v + uv' ]

En este caso,
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