he complex number z1,z2𝑧1,𝑧2 satisfies the equation z+1+8 i=|z|(1+i)𝑧+1+8 𝑖=𝑧1+𝑖, where i=−1−−−√𝑖=-1 then the equation whose roots are |z1|𝑧1 and |z2|𝑧2 is
Question
The complex number satisfies the equation:
where . The goal is to find the equation whose roots are and .
Solution
To find the equation whose roots are given in the form of and based on the initial equation provided, we'll follow the required steps to solve the complex equation.
1. Break Down the Problem
We start with the equation provided: and we need to express this in terms of specific roots and .
2. Relevant Concepts
We recognize that denotes the modulus of the complex number . The term can be simplified, and the question is likely looking for a polynomial with roots related to these complex numbers.
Let’s express in its standard form: where and are real numbers.
3. Analysis and Detail
We now plug into the equation: Simplifying the left side gives:
Now equate the real and imaginary parts:
Real part:
Imaginary part:
Now we have two equations:
- (1)
- (2)
Setting (1) equal to (2): This provides us an expression for :
Substituting back into either equation (let's use (1)): Squaring both sides: Expanding gives: Reorganizing yields:
4. Verify and Summarize
We solve this quadratic equation using the :
Thus: Now substitute back to get :
- For : →
- For : →
The moduli are:
Final Answer
The roots of the desired equation are and . Thus, the equation whose roots are given by these complex numbers can be formulated as: with roots and .
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