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he complex number z1,z2𝑧1,𝑧2 satisfies the equation z+1+8 i=|z|(1+i)𝑧+1+8 𝑖=𝑧1+𝑖, where i=−1−−−√𝑖=-1 then the equation whose roots are |z1|𝑧1 and |z2|𝑧2 is

Question

The complex number z1,z2 z_1, z_2 satisfies the equation:

z+1+8i=z(1+i) z + 1 + 8i = |z|(1 + i)

where i=1 i = \sqrt{-1} . The goal is to find the equation whose roots are z1 |z_1| and z2 |z_2| .

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Solution

To find the equation whose roots are given in the form of z1z1 |z_1| z_1 and z2z2 |z_2| z_2 based on the initial equation provided, we'll follow the required steps to solve the complex equation.

1. Break Down the Problem

We start with the equation provided: z+1+8i=z(1+i) z + 1 + 8i = |z|(1+i) and we need to express this in terms of specific roots z1 z_1 and z2 z_2 .

2. Relevant Concepts

We recognize that z |z| denotes the modulus of the complex number z z . The term 1+i 1 + i can be simplified, and the question is likely looking for a polynomial with roots related to these complex numbers.

Let’s express z z in its standard form: z=x+yi z = x + yi where x x and y y are real numbers.

3. Analysis and Detail

We now plug z z into the equation: (x+yi)+1+8i=x2+y2(1+i) (x + yi) + 1 + 8i = \sqrt{x^2 + y^2}(1+i) Simplifying the left side gives: (x+1)+(y+8)i (x + 1) + (y + 8)i

Now equate the real and imaginary parts:

Real part: x+1=x2+y2 x + 1 = \sqrt{x^2 + y^2}

Imaginary part: y+8=x2+y2 y + 8 = \sqrt{x^2 + y^2}

Now we have two equations:

  1. x+1=x2+y2 x + 1 = \sqrt{x^2 + y^2} (1)
  2. y+8=x2+y2 y + 8 = \sqrt{x^2 + y^2} (2)

Setting (1) equal to (2): x+1=y+8 x + 1 = y + 8 This provides us an expression for y y : y=x7 y = x - 7

Substituting y y back into either equation (let's use (1)): x+1=x2+(x7)2 x + 1 = \sqrt{x^2 + (x - 7)^2} Squaring both sides: (x+1)2=x2+(x7)2 (x + 1)^2 = x^2 + (x - 7)^2 Expanding gives: x2+2x+1=x2+x214x+49 x^2 + 2x + 1 = x^2 + x^2 - 14x + 49 2x+1=x214x+49 2x + 1 = x^2 - 14x + 49 Reorganizing yields: 0=x216x+48 0 = x^2 - 16x + 48

4. Verify and Summarize

We solve this quadratic equation using the x x : x=16±(16)2414821 x = \frac{16 \pm \sqrt{(16)^2 - 4 \cdot 1 \cdot 48}}{2 \cdot 1} x=16±2561922=16±642=16±82 x = \frac{16 \pm \sqrt{256 - 192}}{2} = \frac{16 \pm \sqrt{64}}{2} = \frac{16 \pm 8}{2}

Thus: x=12orx=4 x = 12 \quad \text{or} \quad x = 4 Now substitute back to get y y :

  • For x=12 x = 12 : y=127=5 y = 12 - 7 = 5 z1=12+5i z_1 = 12 + 5i
  • For x=4 x = 4 : y=47=3 y = 4 - 7 = -3 z2=43i z_2 = 4 - 3i

The moduli are: z1=122+52=144+25=169=13 |z_1| = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 z2=42+(3)2=16+9=25=5 |z_2| = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

Final Answer

The roots of the desired equation are z1z1=13(12+5i) |z_1| z_1 = 13(12 + 5i) and z2z2=5(43i) |z_2| z_2 = 5(4 - 3i) . Thus, the equation whose roots are given by these complex numbers can be formulated as: x2(z1+z2)x+z1z2=0 x^2 - (|z_1| + |z_2|)x + |z_1||z_2| = 0 with roots 156+65i 156 + 65i and 2015i 20 - 15i .

This problem has been solved

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