The number of bytes occupied by a character array of 10 elements.(a) 20 bytes(b) 60 bytes(c) 40 bytes(d) 120 bytes

To determine the number of bytes occupied by a character array of 10 elements, we can break down the problem as follows:

1. Break Down the Problem

• We need to find the size of a character array and multiply that by the number of elements in the array.

2. Relevant Concepts

• In C and many other programming languages, a character typically occupies 1 byte.

3. Analysis and Detail

• For a character array of 10 elements: $\text{Total Size} = \text{Number of Elements} \times \text{Size of One Character}$

  • Here, $\text{Number of Elements} = 10$
  • $\text{Size of One Character} = 1 \text{ byte}$

  Thus, $\text{Total Size} = 10 \times 1 = 10 \text{ bytes}$

4. Verify and Summarize

After analyzing, the calculations confirm that the total size of a character array with 10 elements is indeed 10 bytes.

Final Answer

None of the given options (a) 20 bytes (b) 60 bytes (c) 40 bytes (d) 120 bytes are correct. The correct answer is 10 bytes.