One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is832R2R2.5R
Question
One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas.
The molar specific heat of the mixture at constant volume is 832R, 2R, 2.5R.
Solution
It seems like there's a mistake in your question. The molar specific heat of the mixture at constant volume is given as "832R2R2.5R", which doesn't make sense.
However, I can tell you how to calculate the molar specific heat of a mixture of gases.
The molar specific heat at constant volume (Cv) for a monoatomic ideal gas is 3R/2 and for a diatomic ideal gas, it's 5R/2, where R is the gas constant.
If you have equal moles of the two gases, the molar specific heat of the mixture at constant volume would be the average of the two, which is (3R/2 + 5R/2) / 2 = 4R/2 = 2R.
Please check your question and provide the correct information so I can give you a more accurate answer.
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