Explain the formation of ionic compound CaO with electron-dot structure. Atomic numbers of calcium and oxygen are 20 and 8 respectively.

Sure, here is the step by step explanation of the formation of ionic compound CaO with electron-dot structure:

1. Identify the atomic numbers: The atomic number of calcium (Ca) is 20 and that of oxygen (O) is 8.

2. Determine the electron configuration: The electron configuration of a neutral atom is determined by the atomic number. For calcium, the electron configuration is 2,8,8,2. For oxygen, it is 2,6.

3. Identify the valence electrons: The valence electrons are the electrons in the outermost shell of an atom. Calcium has 2 valence electrons and oxygen has 6.

4. Draw the electron-dot structure: The electron-dot structure is a graphical representation of the atom's valence electrons. For calcium, it would be Ca with two dots around it. For oxygen, it would be O with six dots around it.

5. Formation of the ionic compound: In order to achieve a stable electron configuration, calcium will lose its 2 valence electrons to oxygen. This results in a positively charged calcium ion (Ca2+) and a negatively charged oxygen ion (O2-).

6. Write the formula of the ionic compound: The ionic compound formed by calcium and oxygen is calcium oxide (CaO). The positive and negative charges cancel out, resulting in a neutral compound.

7. Draw the electron-dot structure of the ionic compound: The electron-dot structure of CaO would show the Ca ion with no dots around it (since it has lost its valence electrons) and the O ion with eight dots around it (since it has gained two electrons).

So, the formation of the ionic compound CaO involves the transfer of electrons from calcium to oxygen, resulting in a stable electron configuration for both ions.