What is the output of the following code?#include <stdio.h>int main() { int arr[5] = {1, 2, 3, 4, 5}; printf("%d\n", arr[3]); return 0;}

Question

What is the output of the following code?

#include &lt;stdio.h&gt;

int main() {
    int arr[5] = {1, 2, 3, 4, 5};
    printf(&quot;%d\n&quot;, arr[3]);
    return 0;
}

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Solution

The output of the code will be 4.

Here's the step by step explanation:

An integer array named 'arr' of size 5 is declared and initialized with the values 1, 2, 3, 4, 5.
The printf function is used to print the value at the 3rd index of the array 'arr'.
In C, array indexing starts from 0. So, arr[0] is 1, arr[1] is 2, arr[2] is 3, arr[3] is 4, and arr[4] is 5.
Therefore, arr[3] will output 4.
The program then returns 0 and ends.

This problem has been solved

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