What is the output of the following code?#include <stdio.h>int main() { int i = 0; for (; i < 5; i++); printf("%d ", i); return 0;}
Question
What is the output of the following code?#include <stdio.h>int main() { int i = 0; for (; i < 5; i++); printf("%d ", i); return 0;}
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Solution 1
The output of the code will be "5".
Here's the step by step explanation:
- The integer variable
i
is initialized to 0. - The
for
loop will incrementi
by 1 each time it loops untili
is no longer less than 5. Note that the loop body is empty, so it's just incrementingi
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