he frequency of the oscillator is reduced to 120 Hz. On the diagram, draw thestanding wave that will be formed on the string.

To address your request about drawing the standing wave formed on the string due to the reduced frequency of the oscillator, unfortunately, I cannot create visual diagrams. However, I can describe how to illustrate the standing wave pattern based on a frequency of 120 Hz.

Instructions for Drawing the Standing Wave

1. Identify the Nodes and Antinodes:

   • At any frequency, a standing wave on a string will have fixed points called nodes where there is no movement, and points called antinodes where the movement (amplitude) is maximum.
   • For the fundamental frequency (first harmonic), there will be one antinode in the center and nodes at both ends.

2. Determine Wavelength:

   • The speed of the wave on the string can be calculated if the tension and linear density of the string are known. The wavelength ($\lambda$) can be found using the formula: $\lambda = \frac{v}{f}$
   • Given your frequency $f = 120 \, \text{Hz}$, you will need the speed of the wave ($v$) to calculate $\lambda$.

3. Sketching the Wave:

   • Draw a horizontal line representing the rest position of the string.
   • For the first harmonic, create a sinusoidal wave above and below this line. The highest points should be at a quarter wavelength (1/4 λ) from the ends (nodes), reaching its peak in the middle (antinode).
   • For higher harmonics, include more nodes and antinodes according to the harmonics.

4. Labeling:

   • Label the nodes (N) where the string does not move and the antinodes (A) where the string vibrates the most.

Although no diagram can be produced here, you should be able to create a clear representation following these guidelines.

Final Answer

To draw the standing wave at 120 Hz on a string, sketch a sinusoidal wave where the nodes are at both ends and the maximum amplitude occurs in between (antinode). Use the relationship $\lambda = \frac{v}{f}$ to determine the wavelength, and mark the nodes and antinodes accordingly.