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The open E-string on a guitar vibrates with a frequency of 83 Hz. How many cycles does it complete in 5.0 s? *1 point78 cycles88 cycles415 cycles600 cycles

Question

The open E-string on a guitar vibrates with a frequency of 83 Hz. How many cycles does it complete in 5.0 s?

  • 1 point
  • 78 cycles
  • 88 cycles
  • 415 cycles
  • 600 cycles
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Solution

1. Break Down the Problem

We need to calculate how many cycles the E-string completes within a given time (5.0 seconds) using its frequency (83 Hz).

2. Relevant Concepts

The frequency of a wave is defined as the number of cycles it completes per second. It is given by the formula: Total cycles=Frequency (Hz)×Time (s) \text{Total cycles} = \text{Frequency (Hz)} \times \text{Time (s)}

3. Analysis and Detail

Given:

  • Frequency f=83Hz f = 83 \, \text{Hz}
  • Time t=5.0s t = 5.0 \, \text{s}

Using the formula: Total cycles=83Hz×5.0s \text{Total cycles} = 83 \, \text{Hz} \times 5.0 \, \text{s} Calculating this: Total cycles=415cycles \text{Total cycles} = 415 \, \text{cycles}

4. Verify and Summarize

The calculation seems correct since:

  • 83×5=415 83 \times 5 = 415

Final Answer

The E-string completes 415 cycles in 5.0 seconds.

This problem has been solved

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