To find the electrode potential (E°) for the reaction Fe3+ + 3e– → Fe, we need to add the electrode potentials of the two given reactions.

The first reaction is: Fe3+ + e– → Fe2+ ; E° = 0.77 V
The second reaction is: Fe2+ + 2e– → Fe ; E° = –0.44 V

We add these two reactions to get the desired reaction: Fe3+ + 3e– → Fe

The electrode potential (E°) for this reaction is the sum of the electrode potentials of the two given reactions.

So, E° = 0.77 V + (–0.44 V) = 0.33 V

Therefore, the electrode potential for the reaction Fe3+ + 3e– → Fe is 0.33 V.

Question

To find the electrode potential (E°) for the reaction Fe3+ + 3e– → Fe, we need to add the electrode potentials of the two given reactions.

The first reaction is: Fe3+ + e– → Fe2+ ; E° = 0.77 V
The second reaction is: Fe2+ + 2e– → Fe ; E° = –0.44 V

We add these two reactions to get the desired reaction: Fe3+ + 3e– → Fe

The electrode potential (E°) for this reaction is the sum of the electrode potentials of the two given reactions.

So, E° = 0.77 V + (–0.44 V) = 0.33 V

Therefore, the electrode potential for the reaction Fe3+ + 3e– → Fe is 0.33 V.

Knowee AI · Accepted Answer

To find the electrode potential (E°) for the reaction Fe3+ + 3e– → Fe, we need to add the electrode potentials of the two given reactions.

The first reaction is: Fe3+ + e– → Fe2+ ; E° = 0.77 V
The second reaction is: Fe2+ + 2e– → Fe ; E° = –0.44 V

We add these two reactions to get the desired reaction: Fe3+ + 3e– → Fe

The electrode potential (E°) for this reaction is the sum of the electrode potentials of the two given reactions.

So, E° = 0.77 V + (–0.44 V) = 0.33 V

Therefore, the electrode potential for the reaction Fe3+ + 3e– → Fe is 0.33 V.

Given(i) Fe3+ + e– → Fe2+ ; E° = 0.77 V(ii) Fe2+ + 2e– → Fe ; E° = –0.44 VElectrode potential, E° for the reaction,Fe3+ + 3e– → Fe, will be