Find the emf of the cell in which the following reaction takes place at 298 K Ni(s) + 2 Ag+ (0.001 M) → Ni2+ (0.001 M) + 2 Ag (s)

Question

Find the emf of the cell in which the following reaction takes place at 298 K Ni(s) + 2 Ag+ (0.001 M) → Ni2+ (0.001 M) + 2 Ag (s)
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Solution 1

To find the emf of the cell, we need to use the Nernst equation. The Nernst equation is used to calculate the potential of a half-cell in an electrochemical cell, or to calculate the total voltage (electromotive force) for a full electrochemical cell.

The Nernst equation is: E = E° - (RT/nF) * lnQ

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