The EMF of the cell : Ni(s) | Ni2+ (1.0M) || Au 3+ (1.0M) | Au (s) is[ given EoNi2+/Ni -0.25V; E° Au3+ / Au = +1.50V ]
Question
Solution 1
To find the EMF of the cell, we can use the Nernst equation:
Ecell = E°cell - (0.0592/n) * log(Q)
First, let's determine the half-reactions occurring at each electrode:
At the anode (left side): Ni(s) -> Ni2+(aq) + 2e-
At the cathode (right side): Au3+(aq) + 3e- -> Au(s)
Now, we can calculate t Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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