Decreasing order of the hydrogen bonding in following forms of water is correctly represented byA. Liquid waterB. IceC. Impure waterA=B>CB>A>CC>B>AA>B>C
Question
Decreasing order of the hydrogen bonding in following forms of water is correctly represented by
A. Liquid water
B. Ice
C. Impure water
- A = B > C
- B > A > C
- C > B > A
- A > B > C
Solution
The hydrogen bonding in different forms of water depends on the structure and purity of the water.
A. Liquid Water: In liquid water, the molecules are close together and can form hydrogen bonds. However, because the water is in a liquid state, these bonds are constantly being broken and reformed.
B. Ice: In ice, the water molecules are locked into a rigid structure. This allows for a maximum number of hydrogen bonds to form, each water molecule forming four hydrogen bonds with its neighbors.
C. Impure Water: Impure water contains other substances dissolved in it. These substances can interfere with the ability of the water molecules to form hydrogen bonds with each other.
Therefore, the correct order of decreasing hydrogen bonding is B>A>C. Ice has the most hydrogen bonding, followed by liquid water, with impure water having the least.
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