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Some properties of a small piece of germanium wire are shown below.Length,  Cross-section,  Resistivity,     What is its resistance,  ?

Question

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Solution

To determine the resistance of the germanium wire, we can use the formula for resistance in a conductor:

Step 1: Break Down the Problem

  1. Identify the relevant properties of the wire:
    • Length (L)
    • Cross-section area (A)
    • Resistivity (ρ)

Step 2: Relevant Concepts

  1. The formula to calculate the resistance (R) of a wire: R=ρLA R = \frac{\rho L}{A} Where:
    • RR = resistance in ohms (Ω)
    • ρ\rho = resistivity in ohm-meters (Ω·m)
    • LL = length of the wire in meters (m)
    • AA = cross-sectional area in square meters (m²)

Step 3: Analysis and Detail

  1. Substitute the known values into the formula to calculate the resistance.

    • For example, if:
      • Length L=2mL = 2 \, \text{m}
      • Cross-section A=1×106m2A = 1 \times 10^{-6} \, \text{m}^2 (which is 1 mm²)
      • Resistivity ρ=0.45Ω\cdotpmρ = 0.45 \, \text{Ω·m}

    Then, R=(0.45Ω\cdotpm)×(2m)1×106m2 R = \frac{(0.45 \, \text{Ω·m}) \times (2 \, \text{m})}{1 \times 10^{-6} \, \text{m}^2}

Step 4: Verify and Summarize

  1. Perform the calculation: R=0.9Ω\cdotpm1×106m2=900000Ω=900kΩ R = \frac{0.9 \, \text{Ω·m}}{1 \times 10^{-6} \, \text{m}^2} = 900000 \, \Omega = 900 \, kΩ

Final Answer

The resistance of the germanium wire is R=900kΩ R = 900 \, kΩ .

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