In an R−L−C series circuit, if the frequency is less than the resonance frequency,a.XL > XCb.XC = XLc.XC > XLd.

Question

In an R−L−C series circuit, if the frequency is less than the resonance frequency,a.XL > XCb.XC = XLc.XC > XLd.
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Solution 1

In an R-L-C series circuit, if the frequency is less than the resonance frequency, the reactance of the capacitor (Xc) is greater than the reactance of the inductor (XL). So, the correct answer is c. XC > XL.

Here's why:

  1. The inductive reactance (XL) is directly proportional to the frequency (f Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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