In an R−L−C series circuit, if the frequency is less than the resonance frequency,a.XL > XCb.XC = XLc.XC > XLd.
Question
In an R−L−C series circuit, if the frequency is less than the resonance frequency,
- a. XL > XC
- b. XC = XL
- c. XC > XL
- d. XC > XL
Solution
In an R-L-C series circuit, if the frequency is less than the resonance frequency, the reactance of the capacitor (Xc) is greater than the reactance of the inductor (XL). So, the correct answer is c. XC > XL.
Here's why:
-
The inductive reactance (XL) is directly proportional to the frequency (f), which means as the frequency increases, XL increases. The formula for XL is XL = 2πfL.
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The capacitive reactance (XC) is inversely proportional to the frequency, which means as the frequency increases, XC decreases. The formula for XC is XC = 1/(2πfC).
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At resonance frequency, XL equals XC.
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Therefore, if the frequency is less than the resonance frequency, XC must be greater than XL.
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