Find the vertex of quadratic relation by completing the square.y = x2 + 12x + 30
Question
Find the vertex of quadratic relation by completing the square.
Given the quadratic relation:
To find the vertex, we need to complete the square.
Solution
To find the vertex of the quadratic equation y = x² + 12x + 30, we need to complete the square. Here are the steps:
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Rewrite the equation in the form of y = a(x-h)² + k, where (h, k) is the vertex of the parabola.
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To do this, we first need to complete the square for the equation. The equation is currently in the form y = x² + bx + c. We can rewrite this as y = (x² + 12x) + 30.
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To complete the square, we need to add and subtract (b/2)² inside the parenthesis. In this case, b is 12, so (b/2)² = (12/2)² = 36.
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Now, rewrite the equation as y = (x² + 12x + 36 - 36) + 30.
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Simplify the equation to get y = (x + 6)² - 6 + 30.
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Finally, simplify further to get y = (x + 6)² + 24.
So, the vertex of the parabola is (-6, 24).
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