How many moles of KClO3 are needed to form 2.8 L of O2, measured at STP, according to the following reaction: 2KClO3 🡪 2KCl + 3O2
Question
How many moles of KClO3 are needed to form 2.8 L of O2, measured at STP, according to the following reaction:
2KClO3 🡪 2KCl + 3O2
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Solution 1
Step 1: Identify the given information
- Volume of O2 = 2.8 L
- We are at Standard Temperature and Pressure (STP), which means that 1 mole of any gas occupies 22.4 L.
Step 2: Convert the volume of O2 to moles using the molar volume of a gas at STP
- Moles of O2 = Volume of O2 / Molar volume at STP Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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