A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
Question
A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
Solution
To solve this problem, we can use the following kinematic equation:
v^2 = u^2 + 2as
where: v = final velocity u = initial velocity a = acceleration s = distance
Given in the problem: v = 7.10 m/s (final velocity) u = 0 m/s (since the bike starts from rest) s = 35.4 m (distance)
We need to find 'a' (acceleration).
Substituting the given values into the equation:
(7.10 m/s)^2 = (0 m/s)^2 + 2a35.4 m
Solving the equation for 'a' gives:
a = ((7.10 m/s)^2 - (0 m/s)^2) / (2*35.4 m)
a = 0.71 m/s^2
So, the acceleration of the bike is 0.71 m/s^2.
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