A jeepney from rest accelerates uniformly over a time of 3.25 s and covers a distance of15 m. determine the acceleration of the jeepne
Question
A jeepney from rest accelerates uniformly over a time of 3.25 s and covers a distance of 15 m. determine the acceleration of the jeepney.
Solution
To solve this problem, we can use the formula for distance covered under uniform acceleration, which is:
d = ut + 0.5at^2
where: d = distance covered u = initial velocity t = time a = acceleration
Given in the problem: d = 15 m u = 0 (since the jeepney starts from rest) t = 3.25 s
Substituting the given values into the formula, we get:
15 = 0*(3.25) + 0.5a(3.25)^2
Solving for a, we get:
a = 2*15 / (3.25)^2
a = 2.84 m/s^2
So, the acceleration of the jeepney is approximately 2.84 m/s^2.
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