The molar conductivity of 0.1 M CH3COOH solution is 4 S cm2 mol–1. What is the resistivity of the solution ?2200 Ω cm2500 Ω cm2400 Ω cm2000 Ω cm
Question
The molar conductivity of 0.1 M CH₃COOH solution is 4 S cm² mol⁻¹. What is the resistivity of the solution ?
- 2200 Ω cm
- 2500 Ω cm
- 2400 Ω cm
- 2000 Ω cm
Solution
The resistivity of a solution can be calculated using the formula:
Resistivity (ρ) = 1 / Conductivity
In this case, the molar conductivity is given as 4 S cm^2 mol^-1. However, this is the conductivity per mole, and we have a 0.1 M solution. So, the actual conductivity (κ) of the solution is:
κ = Molar Conductivity * Concentration κ = 4 S cm^2 mol^-1 * 0.1 mol/L κ = 0.4 S/cm
Now, we can calculate the resistivity:
ρ = 1 / κ ρ = 1 / 0.4 S/cm ρ = 2.5 Ω cm
So, the resistivity of the solution is 2.5 Ω cm.
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