The equivalent conductivity of 0.1 N CH3COOH at 25 °C is 80 and at infinite dilution 400. The degree of dissociation of CH3COOH is :10.10.20.5

Question

The equivalent conductivity of 0.1 N CH3COOH at 25 °C is 80 and at infinite dilution 400. The degree of dissociation of CH3COOH is :10.10.20.5
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Solution 1

The degree of dissociation (α) can be calculated using the formula:

α = λc / λ∞

where: λc = equivalent conductivity of the solution λ∞ = equivalent conductivity at infinite dilution

Given in the problem: λc = 80 λ∞ = 400

Substituting these values into the formula:

α = 80 / 400 = 0.2

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Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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