The equivalent conductivity of 0.1 N CH3COOH at 25 °C is 80 and at infinite dilution 400. The degree of dissociation of CH3COOH is :10.10.20.5

1. Break Down the Problem

We need to calculate the degree of dissociation ($\alpha$) of acetic acid (CH$_3$COOH). Given data includes:

• Equivalent conductivity ($\Lambda_c$) of 0.1 N solution = 80 S cm²/mol
• Equivalent conductivity at infinite dilution ($\Lambda_0$) = 400 S cm²/mol

2. Relevant Concepts

The degree of dissociation for a weak electrolyte can be calculated using the formula:

$\alpha = \frac{\Lambda_c}{\Lambda_0}$

where:

• $\Lambda_c$ is the equivalent conductivity at the given concentration,
• $\Lambda_0$ is the equivalent conductivity at infinite dilution.

3. Analysis and Detail

Substituting the values into the equation:

$\alpha = \frac{80}{400}$

Now, we can perform the calculation:

$\alpha = 0.2$

4. Verify and Summarize

The calculation shows that the degree of dissociation of acetic acid in this scenario is 0.2, indicating that 20% of the acetic acid molecules dissociate in solution.

Final Answer

The degree of dissociation of CH$_3$COOH is $0.2$ or $20\%$.