The angle at which a water hose should be aimed in order to achieve the greatest horizontal range is 45 degrees. This is based on the physics principle of projectile motion. Here are the steps to understand why:

1. The range (R) of a projectile (in this case, the water from the hose) is given by the equation R = (v^2/g) * sin(2θ), where v is the initial velocity of the water, g is the acceleration due to gravity, and θ is the angle at which the water is launched.

2. To maximize the range, we need to maximize the term sin(2θ). The sine function reaches its maximum value of 1 at an angle of 90 degrees.

3. Therefore, to maximize sin(2θ), we need 2θ = 90 degrees, which gives θ = 45 degrees.

So, to achieve the greatest horizontal range, the water hose should be aimed at an angle of 45 degrees.

Question

The angle at which a water hose should be aimed in order to achieve the greatest horizontal range is 45 degrees. This is based on the physics principle of projectile motion. Here are the steps to understand why:

1. The range (R) of a projectile (in this case, the water from the hose) is given by the equation R = (v^2/g) * sin(2θ), where v is the initial velocity of the water, g is the acceleration due to gravity, and θ is the angle at which the water is launched.

2. To maximize the range, we need to maximize the term sin(2θ). The sine function reaches its maximum value of 1 at an angle of 90 degrees.

3. Therefore, to maximize sin(2θ), we need 2θ = 90 degrees, which gives θ = 45 degrees.

So, to achieve the greatest horizontal range, the water hose should be aimed at an angle of 45 degrees.

Knowee AI · Accepted Answer

The angle at which a water hose should be aimed in order to achieve the greatest horizontal range is 45 degrees. This is based on the physics principle of projectile motion. Here are the steps to understand why:

1. The range (R) of a projectile (in this case, the water from the hose) is given by the equation R = (v^2/g) * sin(2θ), where v is the initial velocity of the water, g is the acceleration due to gravity, and θ is the angle at which the water is launched.

2. To maximize the range, we need to maximize the term sin(2θ). The sine function reaches its maximum value of 1 at an angle of 90 degrees.

3. Therefore, to maximize sin(2θ), we need 2θ = 90 degrees, which gives θ = 45 degrees.

So, to achieve the greatest horizontal range, the water hose should be aimed at an angle of 45 degrees.

At what angle should a water hose be aimed in order for the water to land with the greatest horizontal range?

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At what angle should a water hose be aimed in order for the water to land with the greatest horizontal range?

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