The range of a projectile is maximum, when the angle of projection is:a.60ob.45oc.90od.30o
Question
The range of a projectile is maximum, when the angle of projection is:
a. 60°
b. 45°
c. 90°
d. 30°
Solution
The range of a projectile is given by the formula:
R = (v^2 / g) * sin(2θ)
where: R is the range, v is the initial velocity, g is the acceleration due to gravity, θ is the angle of projection.
The range is maximum when sin(2θ) is maximum. The maximum value of sin(2θ) is 1, which occurs when 2θ = 90 degrees.
Therefore, the range is maximum when the angle of projection θ is 90/2 = 45 degrees.
So, the correct answer is b. 45o.
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