1. Solve M⋅[1,x,y]T =[39,-3,-1]T for x and y, where M=[[1,1,6],[7,6,2],[4,3,1]].
Question
1. Solve M ⋅ [1,x,y]^T = [39,-3,-1]^T
where
M = [[1,1,6],[7,6,2],[4,3,1]]
.
Solution
Sure, let's solve the matrix equation step by step.
First, let's write down the matrix equation:
M * [1, x, y]T = [39, -3, -1]T
where M is a 3x3 matrix:
M = [[1, 1, 6], [7, 6, 2], [4, 3, 1]]
We can rewrite the equation as a system of linear equations:
11 + 1x + 6y = 39 71 + 6x + 2y = -3 41 + 3x + 1*y = -1
Solving this system of equations, we get:
From the first equation, we can express x in terms of y:
x = 39 - 6y - 1
Substitute x into the second equation:
7 + 6*(39 - 6y - 1) + 2y = -3 234 - 36y + 2y = -3 -34y = -237 y = 237 / 34 y = 7
Substitute y = 7 into the first equation:
x = 39 - 6*7 - 1 x = 39 - 42 - 1 x = -4
So, the solution to the system of equations is x = -4 and y = 7.
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