The gas in a balloon occupies 3.50 L at 300 K. At which temperature will the balloon expand to 8.50 L?

This problem can be solved using the ideal gas law, which states that the volume of a gas is directly proportional to its temperature, assuming pressure and the amount of gas are constant. This relationship can be expressed as V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Here are the steps to solve the problem:

1. Convert all temperatures to Kelvin. In this case, the initial temperature is already given in Kelvin (300 K), so no conversion is necessary.

2. Plug the given values into the equation. V1 is 3.50 L, T1 is 300 K, and V2 is 8.50 L. We're solving for T2, the final temperature.

3.50 L / 300 K = 8.50 L / T2

3. Solve for T2. Cross-multiply and divide to get T2 by itself:

T2 = (8.50 L * 300 K) / 3.50 L

4. Calculate the value of T2. This will give you the final temperature in Kelvin at which the balloon will expand to 8.50 L.