A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?
Question
A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?
Solution
The volume of the balloon will increase. This is due to Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant.
Here's a step-by-step explanation:
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Identify the initial volume (V1) and temperature (T1). In this case, V1 is 0.7 L and T1 is 20°C.
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Convert the temperatures from Celsius to Kelvin. The Kelvin scale is used in gas law problems. To convert, add 273.15 to the Celsius temperature. So, T1 is 20 + 273.15 = 293.15 K.
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Identify the final temperature (T2). In this case, T2 is 25°C, which is 25 + 273.15 = 298.15 K.
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Apply Charles's Law, which is V1/T1 = V2/T2. We know V1, T1, and T2, and we want to find V2 (the final volume).
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Solve for V2: V2 = V1 * T2 / T1 = 0.7 L * 298.15 K / 293.15 K = 0.71 L.
So, the volume of the balloon increases to 0.71 L when the temperature is increased to 25°C.
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