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A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?

Question

A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?

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Solution

The volume of the balloon will increase. This is due to Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant.

Here's a step-by-step explanation:

  1. Identify the initial volume (V1) and temperature (T1). In this case, V1 is 0.7 L and T1 is 20°C.

  2. Convert the temperatures from Celsius to Kelvin. The Kelvin scale is used in gas law problems. To convert, add 273.15 to the Celsius temperature. So, T1 is 20 + 273.15 = 293.15 K.

  3. Identify the final temperature (T2). In this case, T2 is 25°C, which is 25 + 273.15 = 298.15 K.

  4. Apply Charles's Law, which is V1/T1 = V2/T2. We know V1, T1, and T2, and we want to find V2 (the final volume).

  5. Solve for V2: V2 = V1 * T2 / T1 = 0.7 L * 298.15 K / 293.15 K = 0.71 L.

So, the volume of the balloon increases to 0.71 L when the temperature is increased to 25°C.

This problem has been solved

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