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Let  A = {a ,b, c , d}, B = {b , d , e ,h}, then  A⊕B  = { a , c , h}Group startsTrue or FalseTrue, unselectedFalse

Question

Let  A = {a ,b, c , d}, B = {b , d , e ,h}, then

A⊕B  = { a , c , h}

Group starts
True or False
True, unselected
False

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Solution

To determine whether the statement A⊕B={a,c,h} A \oplus B = \{ a, c, h \} is true or false, we first need to understand the operation represented by ⊕ \oplus in this context. The operation typically represents the symmetric difference of two sets, which includes elements that are in either of the sets but not in their intersection.

1. ### Break Down the Problem

We have two sets:

  • A={a,b,c,d} A = \{ a, b, c, d \}
  • B={b,d,e,h} B = \{ b, d, e, h \}

We need to compute A⊕B A \oplus B , which is defined as: A⊕B=(A−B)∪(B−A) A \oplus B = (A - B) \cup (B - A)

2. ### Relevant Concepts

  • Set Difference:

    • A−B A - B is the set of elements that are in A A but not in B B .
    • B−A B - A is the set of elements that are in B B but not in A A .
  • Union of Sets: The union of two sets is the set that contains all elements from both sets without duplicates.

3. ### Analysis and Detail

  1. Calculate A−B A - B :

    • A−B={a,b,c,d}−{b,d,e,h}={a,c} A - B = \{ a, b, c, d \} - \{ b, d, e, h \} = \{ a, c \}
  2. Calculate B−A B - A :

    • B−A={b,d,e,h}−{a,b,c,d}={e,h} B - A = \{ b, d, e, h \} - \{ a, b, c, d \} = \{ e, h \}
  3. Calculate the symmetric difference:

    • Now, combine the results: A⊕B=(A−B)∪(B−A)={a,c}∪{e,h}={a,c,e,h} A \oplus B = (A - B) \cup (B - A) = \{ a, c \} \cup \{ e, h \} = \{ a, c, e, h \}

4. ### Verify and Summarize

We found that: A⊕B={a,c,e,h} A \oplus B = \{ a, c, e, h \} The statement A⊕B={a,c,h} A \oplus B = \{ a, c, h \} is incorrect since we also have element e e .

Final Answer

The statement is False.

This problem has been solved

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