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Let  A = {a ,b, c , d}, B = {b , d , e ,h}, then  A⊕B  = { a , c , h}Group startsTrue or FalseTrue, unselectedFalse

Question

Let  A = {a ,b, c , d}, B = {b , d , e ,h}, then

A⊕B  = { a , c , h}

Group starts
True or False
True, unselected
False

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Solution

To determine whether the statement AB={a,c,h} A \oplus B = \{ a, c, h \} is true or false, we first need to understand the operation represented by \oplus in this context. The operation typically represents the symmetric difference of two sets, which includes elements that are in either of the sets but not in their intersection.

1. ### Break Down the Problem

We have two sets:

  • A={a,b,c,d} A = \{ a, b, c, d \}
  • B={b,d,e,h} B = \{ b, d, e, h \}

We need to compute AB A \oplus B , which is defined as: AB=(AB)(BA) A \oplus B = (A - B) \cup (B - A)

2. ### Relevant Concepts

  • Set Difference:

    • AB A - B is the set of elements that are in A A but not in B B .
    • BA B - A is the set of elements that are in B B but not in A A .
  • Union of Sets: The union of two sets is the set that contains all elements from both sets without duplicates.

3. ### Analysis and Detail

  1. Calculate AB A - B :

    • AB={a,b,c,d}{b,d,e,h}={a,c} A - B = \{ a, b, c, d \} - \{ b, d, e, h \} = \{ a, c \}
  2. Calculate BA B - A :

    • BA={b,d,e,h}{a,b,c,d}={e,h} B - A = \{ b, d, e, h \} - \{ a, b, c, d \} = \{ e, h \}
  3. Calculate the symmetric difference:

    • Now, combine the results: AB=(AB)(BA)={a,c}{e,h}={a,c,e,h} A \oplus B = (A - B) \cup (B - A) = \{ a, c \} \cup \{ e, h \} = \{ a, c, e, h \}

4. ### Verify and Summarize

We found that: AB={a,c,e,h} A \oplus B = \{ a, c, e, h \} The statement AB={a,c,h} A \oplus B = \{ a, c, h \} is incorrect since we also have element e e .

Final Answer

The statement is False.

This problem has been solved

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