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A number when divided by 258 gives a remainder equal to 87. Find the remainder when the same number is divided by 43.Options0513

Question

A number when divided by 258 gives a remainder equal to 87. Find the remainder when the same number is divided by 43.

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Solution

1. Break Down the Problem

We are given a number N N which when divided by 258 leaves a remainder of 87. Our task is to find the remainder of N N when divided by 43. We can express the relationship as: N=258k+87 N = 258k + 87 for some integer k k .

2. Relevant Concepts

To find the remainder of N N when divided by 43, we can rewrite the expression: Nmod43=(258k+87)mod43 N \mod 43 = (258k + 87) \mod 43 Using properties of modular arithmetic: (a+b)modm=[(amodm)+(bmodm)]modm (a + b) \mod m = [(a \mod m) + (b \mod m)] \mod m

3. Analysis and Detail

First, we compute 258mod43 258 \mod 43 : 258÷436.0258=43×6+r 258 \div 43 \approx 6.0 \Rightarrow 258 = 43 \times 6 + r Calculating: 43×6=258r=0    258mod43=0 43 \times 6 = 258 \Rightarrow r = 0 \implies 258 \mod 43 = 0 Next, compute 87mod43 87 \mod 43 : 87÷432.087=43×2+r 87 \div 43 \approx 2.0 \Rightarrow 87 = 43 \times 2 + r Calculating: 43×2=86r=1    87mod43=1 43 \times 2 = 86 \Rightarrow r = 1 \implies 87 \mod 43 = 1

Now, substituting back into the equation: Nmod43=(0k+1)mod43=1 N \mod 43 = (0 \cdot k + 1) \mod 43 = 1

4. Verify and Summarize

We've calculated the respective remainders and combined them to find that the remainder when N N is divided by 43 is: Remainder=1 \text{Remainder} = 1

Final Answer

The remainder when the same number is divided by 43 is 1.

This problem has been solved

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