分析以下算法的T(n)x=0;y=0;for (k=1;k<=n;k++)x++;for (i=1;i<=n;i++)for (j=1;j<=n;j++)y++;
Question
Solution 1
The given algorithm consists of two main parts.
- The first loop:
for (k=1;k<=n;k++)x++;
This loop runs 'n' times. Therefore, the time complexity of this loop is O(n).
- The second part:
for (i=1;i<=n;i++)for (j=1;j<=n;j++)y++;
This is a nested loop where both the outer loop and t
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