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Find the number of distinct arrangements of the 8 letters in SPINNING.Two of the same letter are considered identical (not distinct).

Question

Find the number of distinct arrangements of the 8 letters in SPINNING.

Two of the same letter are considered identical (not distinct).

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Solution

To find the number of distinct arrangements of the letters in "SPINNING", we can use the formula for permutations of a multiset. This formula is n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In "SPINNING", there are 8 letters in total, so n = 8.

The letter "S" appears 1 time, so r1 = 1. The letter "P" appears 1 time, so r2 = 1. The letter "I" appears 1 time, so r3 = 1. The letter "N" appears 3 times, so r4 = 3. The letter "G" appears 1 time, so r5 = 1.

Substituting these values into the formula gives us:

8! / (1! * 1! * 1! * 3! * 1!) = 40,320 / (1 * 1 * 1 * 6 * 1) = 6,720.

So, there are 6,720 distinct arrangements of the letters in "SPINNING".

This problem has been solved

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