Find the number of distinct arrangements of the 8 letters in GIGGLING.Two of the same letter are considered identical (not distinct).
Question
Find the number of distinct arrangements of the 8 letters in GIGGLING.
Two of the same letter are considered identical (not distinct).
Solution
To solve this problem, we use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.
In the word GIGGLING, there are 8 letters in total.
The letter G appears 3 times, the letter I appears 2 times, and the letters N, L appear 1 time each.
So, we have:
n = 8 (total number of letters) r1 = 3 (number of G's) r2 = 2 (number of I's) r3 = 1 (number of N's) r4 = 1 (number of L's)
Substitute these values into the formula:
Number of arrangements = 8! / (3! * 2! * 1! * 1!)
= 40320 / (6 * 2 * 1 * 1)
= 40320 / 12
= 3360
So, there are 3360 distinct arrangements of the letters in GIGGLING.
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