How many different alkenes result when 3-bromo-3-methylheptane is treated with a strong base?Select answer from the options below46  352

The answer is 3.

Here's the step-by-step explanation:

1. The compound 3-bromo-3-methylheptane is a halogenated alkane. When treated with a strong base, it undergoes elimination reaction to form an alkene.

2. The bromine atom is on the third carbon atom, and there is a methyl group on the same carbon. This means that the bromine atom can be removed and a double bond can be formed in three different locations: between the second and third carbon atoms, between the third and fourth carbon atoms, and between the third and fifth carbon atoms.

3. Each of these locations will result in a different alkene, so there are three different alkenes that can be formed.

Therefore, the correct answer is 3.