An organic compound has C, H and N in ratio 9 : 1 : 3.5 by weight then determine empirical formula of compound
Question
An organic compound has C, H and N in ratio 9 : 1 : 3.5 by weight then determine empirical formula of compound
Solution
To determine the empirical formula of the compound, we need to convert the weight ratio to a mole ratio, as the empirical formula is based on the ratio of moles, not weight.
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First, we need to convert the weight ratio to moles. The atomic masses of C, H, and N are approximately 12 g/mol, 1 g/mol, and 14 g/mol, respectively.
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Divide the given weight ratio by the atomic masses to get the mole ratio:
For C: 9/12 = 0.75 mol For H: 1/1 = 1 mol For N: 3.5/14 = 0.25 mol
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Now, we have the mole ratio as 0.75 : 1 : 0.25. To simplify this, we divide all values by the smallest value (0.25):
For C: 0.75/0.25 = 3 For H: 1/0.25 = 4 For N: 0.25/0.25 = 1
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Therefore, the empirical formula of the compound is C3H4N.
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