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An organic compound has C, H and N in ratio 9 : 1 : 3.5 by weight then determine empirical formula of compound

Question

An organic compound has C, H and N in ratio 9 : 1 : 3.5 by weight then determine empirical formula of compound

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Solution

To determine the empirical formula of the compound, we need to convert the weight ratio to a mole ratio, as the empirical formula is based on the ratio of moles, not weight.

  1. First, we need to convert the weight ratio to moles. The atomic masses of C, H, and N are approximately 12 g/mol, 1 g/mol, and 14 g/mol, respectively.

  2. Divide the given weight ratio by the atomic masses to get the mole ratio:

    For C: 9/12 = 0.75 mol For H: 1/1 = 1 mol For N: 3.5/14 = 0.25 mol

  3. Now, we have the mole ratio as 0.75 : 1 : 0.25. To simplify this, we divide all values by the smallest value (0.25):

    For C: 0.75/0.25 = 3 For H: 1/0.25 = 4 For N: 0.25/0.25 = 1

  4. Therefore, the empirical formula of the compound is C3H4N.

This problem has been solved

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