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If X walks less fast than Y, and Y walks as fast but not faster than Z; then, as compared to X, Z walks:

Question

If X walks less fast than Y, and Y walks as fast but not faster than Z; then, as compared to X, Z walks:

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Solution

To analyze the given statements:

  1. Understanding the relationships:

    • X walks slower than Y: X<Y X < Y
    • Y walks as fast as Z but not faster: YZ Y \leq Z
  2. Combining the inequalities:

    • From X<Y X < Y and YZ Y \leq Z , we can conclude that: X<YZ X < Y \leq Z
  3. Conclusion:

    • This means that Z walks at the same speed as Y or faster than Y, which in turn means that Z walks faster than X.

Final Answer

Z walks faster than X.

This problem has been solved

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