A voltage divider has a 12 V power source and needs an output voltage of 8 V. What ratio of $\frac{R_2}{R_{total}}$R2Rtotal is required?
Question
Solution
The voltage divider equation is given by:
V_out = V_in * (R2 / (R1 + R2))
where:
- V_out is the output voltage, which is 8V in this case
- V_in is the input voltage, which is 12V in this case
- R1 and R2 are the resistances in the voltage divider
We are asked to find the ratio R2 / (R1 + R2). Let's denote this ratio as x for simplicity. So, we have:
8V = 12V * x
Solving for x gives:
x = 8V / 12V = 2 / 3
So, the required ratio of R2 / (R1 + R2) is 2/3.
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