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A voltage divider has a 12 V power source and needs an output voltage of 8 V. What ratio of $\frac{R_2}{R_{total}}$R2​Rtotal​​​ is required?

Question

A voltage divider has a 12 V power source and needs an output voltage of 8 V. What ratio of R2Rtotal \frac{R_2}{R_{total}} is required?

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Solution

The voltage divider equation is given by:

V_out = V_in * (R2 / (R1 + R2))

where:

  • V_out is the output voltage, which is 8V in this case
  • V_in is the input voltage, which is 12V in this case
  • R1 and R2 are the resistances in the voltage divider

We are asked to find the ratio R2 / (R1 + R2). Let's denote this ratio as x for simplicity. So, we have:

8V = 12V * x

Solving for x gives:

x = 8V / 12V = 2 / 3

So, the required ratio of R2 / (R1 + R2) is 2/3.

This problem has been solved

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