A voltage divider has a 3.0 Ω and a 6.0 Ω resistor in series with a 12 V power supply. What is the output voltage across the 3.0 Ω resistor?

The voltage divider rule states that the voltage across an individual resistor in a series circuit is given by the formula:

Vout = Vin * (R2 / (R1 + R2))

Where:

• Vout is the output voltage across the resistor of interest
• Vin is the input voltage supplied by the power source
• R1 and R2 are the resistances of the two resistors

In this case, we want to find the output voltage across the 3.0 Ω resistor (R2), with a 12 V power supply (Vin), and the other resistor being 6.0 Ω (R1).

Substituting these values into the formula, we get:

Vout = 12V * (3.0 Ω / (6.0 Ω + 3.0 Ω))

Solving the equation:

Vout = 12V * (3.0 Ω / 9.0 Ω)

Vout = 12V * 0.333

Vout = 4V

So, the output voltage across the 3.0 Ω resistor is 4 volts.