A water pump is pumping up water from a well which is 120 m deep.How much work must be done by the pump to raise 2 kg of water?(g=9.8 m s^-2)
Question
A water pump is pumping up water from a well which is 120 m deep. How much work must be done by the pump to raise 2 kg of water? (g=9.8 m s^-2)
Solution
The work done by the pump to raise the water can be calculated using the formula for work done, which is:
Work Done = Force x Distance
In this case, the force is the weight of the water, which can be calculated using the formula:
Weight = Mass x Gravity
So, let's calculate the weight of the water first:
Weight = Mass x Gravity = 2 kg x 9.8 m/s^2 = 19.6 N
Now, we can calculate the work done:
Work Done = Force x Distance = Weight x Depth of well = 19.6 N x 120 m = 2352 J
So, the pump must do 2352 Joules of work to raise 2 kg of water from a well 120 m deep.
Similar Questions
A 5 kg object is lifted 10 meters vertically upward. What is the work done against gravity? (Assume g=9.8m/s²)Select one:a.490 Jb.100 Jc.50 Jd.980 J
A hemispherical tank, 10 ft in diameter is full of liquid (density: 40 lb/ft3). Find the work required to pump the water out of the top of the tank.
A boy lifts a 1 kg block by 1 m. The work done by the boy is: (g = 9.8 metre per second squared)
Calculate power if a pump which can lift 400kg of water through a height of 10m in 20secs?
How much work W is done in lifting a 30-kg sandbag to a height of 9 m? (Use 9.8 m/s2 for g. Round your answer to the nearest integer.)W =
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.