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Find the value of – ab if 2 2 5a 4b a 4b 04     . a and b are real numbers.

Question

Find the value of – ab if

22+5a4b+a+4b+0=0 2^2 + 5a - 4b + a + 4b + 0 = 0

where a and b are real numbers.

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Solution

To find the value of – ab, we can start by simplifying the given expression step by step.

Given expression: 2^2 + 5a - 4b + a - 4b + 0^4

Step 1: Simplify the exponents 2^2 = 4 0^4 = 0

Simplified expression: 4 + 5a - 4b + a - 4b + 0

Step 2: Combine like terms 4 + a + a + 5a - 4b - 4b + 0

Combining the terms with 'a', we get: 4 + 7a - 4b - 4b + 0

Combining the terms with 'b', we get: 4 + 7a - 8b + 0

Step 3: Simplify further 4 + 7a - 8b

Therefore, the value of – ab is 7a - 8b.

This problem has been solved

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