How many times the cout statement will executes for the following code?for(j=1;j<=10;j =j-1) { cout<<”Print J 10 times”; }

Break Down the Problem

1. Understand the Loop: We have a for-loop with the initialization, condition, and increment specified as:

   • Initialization: j = 1
   • Condition: j <= 10
   • Increment: j = j - 1

2. Analyze the Loop Behavior: The loop starts with j initialized to 1 and will continue to execute as long as j is less than or equal to 10. However, the increment decreases j rather than increasing it.

Relevant Concepts

1. For-Loop Structure: A typical for-loop executes the block of code as long as the condition evaluates to true.
2. Infinite Loop Recognition: Since j starts at 1 and is decremented, the condition j <= 10 will always be true for all iterations, as j will continuously take negative values.

Analysis and Detail

1. Initial State: At the start, j = 1 (which is true for the condition).
2. First Execution: The loop prints "Print J 10 times".
3. Subsequent Values: After the first iteration, j becomes 0, then -1, -2, etc. The statement continues executing because the condition remains true.
4. Conclusion: Thus, the loop does not terminate properly and creates an infinite loop situation.

Verify and Summarize

• Since the value of j decreases indefinitely, the loop does not exit and will execute the cout statement endlessly.

Final Answer

The cout statement will execute infinitely due to the decrementing value of j.