. A body attains a velocity of 25 ms−1 in 2s with an acceleration of 4ms−2 . The displacement of the body is:

To solve this problem, we need to use the second equation of motion, which is:

s = ut + 1/2at^2

where: s = displacement u = initial velocity t = time a = acceleration

From the problem, we know that the final velocity (v) is 25 m/s, the time (t) is 2 seconds, and the acceleration (a) is 4 m/s^2. However, we don't know the initial velocity (u).

We can find the initial velocity using the first equation of motion:

v = u + at

Rearranging for u gives:

u = v - at

Substituting the known values gives:

u = 25 m/s - 4 m/s^2 * 2 s = 17 m/s

Now we can find the displacement. Substituting the known values into the second equation of motion gives:

s = 17 m/s * 2 s + 1/2 * 4 m/s^2 * (2 s)^2 s = 34 m + 8 m = 42 m

So, the displacement of the body is 42 meters.