A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the displacement of the body.

To find the displacement of the body, we need to consider the motion in two parts: the upward motion and the downward motion.

1. Upward motion: The body rises vertically upward to a height of 100 m in 5 seconds. We can use the equation of motion: s = ut + (1/2)at^2 where s is the displacement, u is the initial velocity, t is the time, and a is the acceleration.

Given: Initial velocity, u = 0 m/s (since the body starts from rest) Time, t = 5 s Acceleration, a = -9.8 m/s^2 (negative because it acts in the opposite direction to the motion)

Using the equation of motion, we can calculate the displacement during the upward motion: s1 = (0)(5) + (1/2)(-9.8)(5)^2 s1 = 0 + (-4.9)(25) s1 = -122.5 m

2. Downward motion: The body comes back to the same position after another 5 seconds. During this time, the body is moving downward. The initial velocity is the final velocity of the upward motion, which is 0 m/s. The acceleration remains the same, -9.8 m/s^2.

Using the equation of motion, we can calculate the displacement during the downward motion: s2 = (0)(5) + (1/2)(-9.8)(5)^2 s2 = 0 + (-4.9)(25) s2 = -122.5 m

The displacement of the body is the sum of the displacements during the upward and downward motions: Displacement = s1 + s2 Displacement = -122.5 m + (-122.5 m) Displacement = -245 m

Therefore, the displacement of the body is -245 meters.