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f the probability that P will live 20 years is 1/2 and that B will live 20 years is 1/2, then what is the probability that both will live 20 years?

Question

If the probability that P will live 20 years is 12 \frac{1}{2} and that B will live 20 years is 12 \frac{1}{2} , then what is the probability that both will live 20 years?

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Solution

1. Break Down the Problem

We need to find the probability that both P and B will live for 20 years. Given that:

  • The probability that P will live for 20 years, P(P)=12 P(P) = \frac{1}{2}
  • The probability that B will live for 20 years, P(B)=12 P(B) = \frac{1}{2}

2. Relevant Concepts

Since the life spans of P and B are assumed to be independent events, we can use the multiplication rule of probabilities for independent events: P(A and B)=P(A)×P(B) P(A \text{ and } B) = P(A) \times P(B)

3. Analysis and Detail

We will apply this rule to find the combined probability: P(P and B)=P(P)×P(B)=12×12 P(P \text{ and } B) = P(P) \times P(B) = \frac{1}{2} \times \frac{1}{2}

4. Verify and Summarize

Calculating the product: P(P and B)=12×12=14 P(P \text{ and } B) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} Thus, the probability that both P and B will live for 20 years is 14 \frac{1}{4} .

Final Answer

The probability that both P and B will live 20 years is 14 \frac{1}{4} .

This problem has been solved

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