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Q 56. If three positive numbers x, y and z are in A.P. such that xyz = 27 then the minimum possible value of y is: Ops: A. 1.3 B. 3 C. 6 D. 6.3

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Q 56. If three positive numbers x, y and z are in A.P. such that xyz = 27 then the minimum possible value of y is: Ops: A. 1.3 B. 3 C. 6 D. 6.3
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Solution 1

This problem can be solved using the Arithmetic Progression (AP) and AM-GM inequality concepts.

Given that x, y, and z are in AP, we can write them as:

x = y - d, z = y + d,

where d is the common difference.

Also, given that xyz = 27, we can substitute x and z from above:

(y - d)(y)(y + d) = 27 Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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