If three positive numbers a, b and c are in A.P. such that abc=8, then the minimum possible value of b is:
Question
Solution 1
In an arithmetic progression (A.P.), the middle term (b in this case) is the average of the other two terms. So, we can write b = (a + c) / 2.
Given that abc = 8, we can substitute b into this equation to get: a * (a + c) / 2 * c = 8.
Solving this equation for c, we get c = 16 / a^2.
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